C# trim comma from end of string
WebJul 10, 2024 · TrimEnd () method is used to remove the occurrences of a set of characters specified in an array from the ending of the current String object. Syntax for TrimStart () … WebIn the example code, we use the Replace method to remove all occurrences of the comma character , from the input string input. Using Trim method: The Trim method removes …
C# trim comma from end of string
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WebThe trim method returns a new string instead of modifying the value of the current instance, in which all the starting and ending whitespace characters will be removed. If the string … WebDec 12, 2000 · int index = file.IndexOf (','); string output = index > 0 ? file.Substring (0, index).Trim () : file; You can also use Split as others have suggested, but this overload would provide better performance, since it stops evaluating the string after the first comma is found: string output = file.Split (new [] { ',' }, 2) [0].Trim (); Share
WebAug 26, 2010 · Trim - Removes all occurrences of white space characters from the beginning and end of this instance. MSDN-Trim Under this definition removing only last character from string is bad solution. So if we want to "Trim last character from string" we should do something like this Example as extension method: WebPay attention that TrimEnd removes all the trailing occurrences from the string, so if the string has 2 comma in the end TrimEnd will remove both. – Guido Preite Apr 8, 2013 at 12:49 2 This should be the accepted answer, IMHO. Short and sweet is usually best in terms of readability and long term code support. – Andrew Grothe Apr 8, 2013 at 13:49
WebIf you only want to strip the quotes from the ends of the string (not the middle), and there is a chance that there can be spaces at either end of the string (i.e. parsing a CSV format file where there is a space after the commas), then you … WebBut if you really want to remove the last comma in a string, you should find the index of the last comma and remove it like this: string s = "1,5,12,34,12345"; int index = s.LastIndexOf (','); Console.WriteLine (s.Remove (index, 1)); Output will be: 1,5,12,3412345. Here is a …
WebDec 6, 2024 · C# has three string instance methods to trim specific characters from a string. Trim () removes characters from the start and end of a string. TrimStart () cuts away characters from the string’s start. And TrimEnd () removes from the string’s tail end. We call each method on a string instance. And they all return a new, likely modified string.
WebDec 24, 2010 · I have some fields returned by a collection as 2.4200 2.0044 2.0000 I want results like 2.42 2.0044 2 I tried with String.Format, but it returns 2.0000 and setting it to N0 rounds the other val... simplify dealershipWebThe string that remains after all white-space characters are removed from the start and end of the current string. If no characters can be trimmed from the current instance, the method returns the current instance unchanged. Examples. The following example uses the String.Trim() method to remove any extra white space from strings entered by the ... simplify debts splitwiseWebOct 5, 2012 · You may use String.Empty or "" to replace double quotes with an empty string, instead of single space ' '. So your statement should be: rowString = rowString.Replace ("\"", string.Empty).Trim (); (Remember to pass double quote as a string "\"", since the method overload with string.Empty will require both the parameters … raymond trainhamWebString.TrimEnd () returns a string with white-spaces trimmed from the end: " A String ".TrimEnd () -> " A String" None of the methods modify the original string object. (In some implementations at least, if there are no white-spaces to be trimmed, you get back the same string object you started with: simplify definedWebAug 2, 2012 · Firstly, I'd try to avoid including the values themselves directly. Use parameters where possible - it's less simple for IN(x, y, z) style parameters, but you can either use a table-valued parameter or simply dynamically create the parameter list (e.g. to IN(@p0, @p1, @p2)). Secondly, I'd avoid using string concatenation in a loop - use … raymond tracing actorraymond trailray e 10WebI have the following string: ",'first string','more','even more'" I want to transform this into an Array but obviously this is not valid due to the first comma. How can I remove the first comma f... raymond train derailed