Webb6 sep. 2024 · According to the question, Digits that can be used = 3,5,7,8,9 Since, no digits can be repeated, The number of integers is 5P5 = 5! = 120 For a four-digit integer to be greater than 7000, The four-digit integer should begin with 7,8 or 9. The number of such integer = 3 × 4P3 =3 × 4P3 = 3 (24) =72 Therefore, the total no of ways = 120+72 … WebbOf the three-digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two? A 90; B 82; C 80; D 45; E 36; Show Answer. Previous Next. GMAT Test; AWA; Critical Reasoning; Data Sufficiency; Integrated Reasoning;
[Solved] While writing all the numbers from 700 to 1000, how
Webb14 okt. 2024 · The third case can be 7zz, where z is the (same) tens and units digits and z can be any digit from 0 to 9 except 7. So there are also 9 such numbers. Therefore, … WebbIn other words, for counting the number of permutations in this question, we should multiply 3 possibilities by 2 possibilities by 1 possibility: So there are Six three-digit positive integers that can be formed from the digits 3, 4, and 8. In fact, we could list them all if we really wanted to: 348, 384, 438, 483, 834, and 843. microsoft tabs game download
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Webb14 juli 2024 · a = num/100; To get the middle digit we need to get rid of the least significant digit first by dividing by 10 and then mod that by 10. b = (num/10)%10; For the least significant digit all you have to do is the number mod 10. c = num%10; You can then compare these numbers to find the minimum. WebbOf the three-digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two ... 999 [3 integers] All three digits are different use the slot method 3 9 7 = 216 299 - (219) = 80. If s and t are positive integers such that s/t = 64.12, which of the following could be the ... WebbSOLUTION: Consider all positive integers with three different digits. (Note that zero cannot be the first digit.) Find the number of them which are: (a) greater than 700; (b) odd; (c) divi Algebra: Combinatorics and Permutations Solvers Lessons Answers archive Click here to see ALL problems on Permutations microsoft tabs vs spaces